Int b 010
WebInt a,b; A=1; Syntax1: b=++a; pre-increment i.e b=a; o/p: a=2 b=2 First, evaluate the expression and then increment the value of “ a “ by 1 Syntax 2:- b=a++, post-increment o/p: a=2 b=1 First, decrement the value of “a” by 1 and then evaluate the expression Syntax 3: - b=-a; pre decrement o/p : a=0 b=0. WebStudy with Quizlet and memorize flashcards containing terms like Suppose that p1 and p2 are both pointers to the same dynamic integer variable; y is a local integer variable. After the execution of which of the statements below is the pointer variable p1 considered a dangling pointer (not pointing to a valid memory address)? a. p1 = p2; b. p1 = 0; c. p2 = 0; d. p1 = &y; …
Int b 010
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As everybody mentioned here that 010 is an Octal Integer literal . The leading 0 specifies that it is an octal representation . Actual value will be : 1*8^1 + 0*8^0 = 8 (decimal) = 1000 (binary-only last 4 digits) Now coming back to the SOP : System.out.println (010 4); Applying Bitwise OR on 010 and 4 (considering only the last 4 digits) => WebQue. int *b [10]; which is true for b. a. The definition only allocates 10 pointers and does not initialize them. b. Initialization must be done explicitly. c. The definition only allocates 10 …
Web⇒ What is the output of this C code? #include void main() { char a = 'A'; char b = 'B'; int c = a + b % 3 - 3 * 2; printf("%d\n", c); } 42 47 59 63 ⇒ What is the output of this C code? #include int main() { unsigned int a = 10; a = ~a; printf("%d\n", a); }-9-10-11-12 ⇒ If p and q are assigned the values 2 and 3 respectively then the ...
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